Jumlah 10 suku pertama dari deret geometri 1/4 + 1/2 + 1 + 2 + 4 +..... adalah
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Jawaban:
[tex]a = \frac{1}{4} \\ r = \frac{u2}{u1} = \frac{ \frac{1}{2} }{ \frac{1}{4} } = \frac{1}{2} \times \frac{4}{1} = \frac{4}{2} = 2[/tex]
mencari jumlah S10
[tex]sn = \frac{a( {r}^{n} - 1)}{r - 1} \\ s10 = \frac{ \frac{1}{4} ( {2}^{10} - 1) }{2 - 1} \\ s10 = \frac{ \frac{1}{4}(1024 - 1) }{1} \\ s10 = \frac{1}{4} (1023) \\ s10 = \frac{1023}{4} \\ s10 = 255 \frac{3}{4} [/tex]
